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3x^2-72x+81=0
a = 3; b = -72; c = +81;
Δ = b2-4ac
Δ = -722-4·3·81
Δ = 4212
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4212}=\sqrt{324*13}=\sqrt{324}*\sqrt{13}=18\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-18\sqrt{13}}{2*3}=\frac{72-18\sqrt{13}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+18\sqrt{13}}{2*3}=\frac{72+18\sqrt{13}}{6} $
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